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发表于 2009-5-8 15:06
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引用第10楼franco于2009-05-07 20:39发表的 :
" y2 A3 [( n; v% B- cThe oscillating member is moved backwards and forwards through an angle of 90° (45° on % T+ W" J. X3 z% R
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per - f. A# [5 Z# G* \
min. A flexing is one movement, either backwards or forwards. After 10 000 flexings, the
( b3 C6 d, g- U0 r, Y, T3 w4 g) xsample is turned through 90° about the centre line of the cord guard. * v1 l& q$ Y4 [
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....... 是的,这段话写的确实很明白,但是我估计你还是理解错了。. X- ?3 W, c+ s6 L6 o% F( P
( _. a/ K. q8 i, r1 p翻译成中文的主要意思就是:5 c# K3 y8 O) A: \& G$ p: u
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The oscillating member is moved backwards and forwards through an angle of 90° (45° on & ]% ?8 z' A0 [7 y$ \. r- J
either side of the vertical), the number of flexings being 20 000 and the rate of flexing 60 per
( s: z4 l' \4 M |9 Tmin. - 摇摆装置能够在90°的范围内前后摆动(其中这个90°指的是沿垂直位置两边各45°),以每分钟60次的频率摇摆20000次。7 k9 x& X3 O) o: g, J
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这句话讨论的是仪器的摆动机构要满足的特性,就是要能在90°的范围内前后摆动,如果只能在45°的范围内摆动的话,这个设备就是不符合要求的。这句话并没有涉及到一个摆动周期如何定义啊。3 A- k$ [, D9 k9 z
# d8 w, v( A2 _: HAfter 10 000 flexings, the sample is turned through 90° about the centre line of the cord guard. - 10000次摆动之后,将样品沿着电线防护套的中心线转动90°。
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这句话说的是总共20000次的摆动样品应该在两个位置分两次完成而已,同样没有涉及到摆动周期的解释和说明。( O" a* k3 n+ i! l, d, R
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最重要的一句话应该是:A flexing is one movement, either backwards or forwards. - 一次摇摆就是一次移动,无论是向后还是向前的。
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* W9 j0 r+ x" b& y+ D+ \这句话虽然容易引起歧义,但是仔细考虑一下也不是很难理解。可以看出,1个摆动周期就是单次的向前或者向后的移动。摇摆机构是在总共90°范围内摆动,那不管是向前还是向后的摆动角度都是45°了。由此可以得出1个摇摆周期就是45°而不是我们通常认为的90°。
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摘抄UL 745-1标准中的相关章节如下,关于这个问题解释的非常清楚,供大家参考参考:
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A flexing is one movement, either backwards or forwards. That is, from vertical to 45° in one direction is the first flex, from there back to vertical is the second flex, from vertical to the opposite 45° is the third flex, from there back to vertical is the fourth flex, continuing until 10000 flexes have occurred. |
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